判断是不是回文字符串

我见到的最不要脸的写法是这样的:

python:

return s == s[::-1]



#include <iostream>

#include <vector>
#include <algorithm>
#include <stack>
using namespace std;


bool isHuiWen(string s) {
if (s.empty()) return true;
if (s.size() == 1) return true;
int sLen = s.size();
if (s[0] == s[sLen - 1]) {
return isHuiWen(s.substr(1, sLen - 2));
}
return false;
}
bool isHuiWen2(string s) {
if (s.empty()) return true;
//if (s.size() == 1) return true;
int i = 0;
int j = s.size()-1;
while(i < j) {
if (s[i] == s[j]) {
i++;
j--;
}
else
return false;
}
return true;
}
int main()
{
//Solution s = Solution();
cout << isHuiWen2("abcddcba") << endl;
system("pause");
return 0;
}

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转载自blog.csdn.net/weixin_36149892/article/details/80170602