DreamGrid went to the bookshop yesterday. There are books in the bookshop in total. Because DreamGrid is very rich, he bought the books according to the strategy below:
- Check the books from the 1st one to the -th one in order.
- For each book being checked now, if DreamGrid has enough money (not less than the book price), he'll buy the book and his money will be reduced by the price of the book.
- In case that his money is less than the price of the book being checked now, he will skip that book.
BaoBao is curious about how rich DreamGrid is. You are asked to tell him the maximum possible amount of money DreamGrid took before buying the books, which is a non-negative integer. All he knows are the prices of the books and the number of books DreamGrid bought in total, indicated by .
Input
There are multiple test cases. The first line of the input contains an integer , indicating the number of test cases. For each test case:
The first line contains two integers and (, ), indicating the number of books in the bookshop and the number of books DreamGrid bought in total.
The second line contains non-negative integers (), where indicates the price of the -th book checked by DreamGrid.
It's guaranteed that the sum of in all test cases will not exceed .
<h4< dd="">Output
For each test case output one line.
If it's impossible to buy books for any initial number of money, output "Impossible" (without quotes).
If DreamGrid may take an infinite amount of money, output "Richman" (without quotes).
In other cases, output a non-negative integer, indicating the maximum number of money he may take.
<h4< dd="">Sample Input
4 4 2 1 2 4 8 4 0 100 99 98 97 2 2 10000 10000 5 3 0 0 0 0 1
<h4< dd="">Sample Output
6 96 Richman Impossible
开始用思维交了一发，WA了。。。
然后错误的发现了自己的“错误”
然后就想到了二分答案
结果。。。崩了。。。
赛后上网搜了一下。。确实是贪心思维题，而且自己的想法没有太大偏差。。。哎
以后还是好好练啊，差的有点多
上代码
1 /*
2 加油，别忘记你写这段话时候的心情
3 如临深渊，如履薄冰
4 */
5 #include<bits/stdc++.h>
6 #include<cstdio>
7 #include<cstring>
8 #include<vector>
9 #include<algorithm>
10 #include<cmath>
11 #include<iostream>
12 #include<queue>
13 #include<set>
14 using namespace std;
15 typedef long long ll;
16 typedef unsigned long long ull;
17 const int maxn = 300000+100;
18 const ll maxn1 = 1e14;
19
20 vector<int> a; 21 int t,x,n,m; 22 23 int main() 24 { 25 int cnt = 0; 26 scanf("%d",&t); 27 while(t--) 28 { 29 a.clear(); 30 cnt = 0; 31 scanf("%d%d",&n,&m); 32 for(int i = 1; i <= n; i++) 33 { 34 scanf("%d",&x); 35 if(x == 0) cnt++; 36 else a.push_back(x); 37 } 38 if(n == m) 39 { 40 printf("Richman\n"); 41 continue; 42 } 43 if(cnt > m) 44 { 45 printf("Impossible\n"); 46 continue; 47 } 48 m -= cnt; 49 ll sum = 0; 50 ll mx = maxn1; 51 for(int i = 0; i < n - cnt; i++) 52 { 53 if(i < m) sum += a[i]; 54 else 55 { 56 if(mx > a[i]) 57 { 58 mx = a[i]; 59 } 60 } 61 } 62 printf("%lld\n",sum+mx-1); 63 } 64 return 0; 65 }