python 读取文件夹下所有文件名

os.walk() 返回的是generator
os.listdir() 返回的是list

import os         
file_dir = r"D:\\code\\1"
i = 1
a = os.walk(file_dir)
b = None
for root, dirs, files in os.walk(file_dir):  
    print(i)
    i += 1
    print(root) #当前目录路径  
    print(dirs) #当前路径下所有子目录  
    print(files) #当前路径下所有非目录子文件 
print(b)

会递归将目录下每个文件夹的内容都输出
输出

1
D:\code\1
[‘123’, ‘234’]
[‘flash_back_binlog.000000002’, ‘flash_back_binlog.000000003’, ‘flash_back_binlog.000001’]
2
D:\code\1\123
[‘123_1’]
[‘flash_back_binlog.000000001’, ‘flash_back_binlog.000000002’]
3
D:\code\1\123\123_1
[]
[‘flash_back_binlog.000000001’, ‘flash_back_binlog.000000002’]
4
D:\code\1\234
[‘234_1’]
[‘flash_back_binlog.000000001’, ‘flash_back_binlog.000000002’]
5
D:\code\1\234\234_1
[]
[‘flash_back_binlog.000000001’, ‘flash_back_binlog.000000002’]
None

import os  
path = r"D:\\code\\1"
print(os.listdir(path))

只会将当前层的文件盒文件夹输出

输出
[‘123’, ‘234’, ‘flash_back_binlog.000000002’, ‘flash_back_binlog.000000003’, ‘flash_back_binlog.000001’]

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转载自blog.csdn.net/pynash123/article/details/88310545