15.判断树的子结构

输入两棵二叉树A,B,判断B是不是A的子结构。(ps:我们约定空树不是任意一个树的子结构)

链表跟树真的头大,毫无头绪,这是牛客大佬暴力解:

/**
public class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;

    public TreeNode(int val) {
        this.val = val;

    }

}
*/
public class Solution {
    public boolean HasSubtree(TreeNode root1,TreeNode root2) {
        if(root1==null||root2==null){
           return false;
       }
        return isSubtree(root1,root2)||HasSubtree(root1.left,root2)||HasSubtree(root1.right,root2);
    }
    
    public boolean isSubtree(TreeNode root1,TreeNode root2){
        if(root2==null){
            return true;
        }
        if(root1==null){
            return false;
        }
        if(root1.val==root2.val){
            return isSubtree(root1.left,root2.left)&&isSubtree(root1.right,root2.right);
        }else{
            return false;
        }
    }
}

  

猜你喜欢

转载自www.cnblogs.com/wzQingtTian/p/10662273.html