H. Mo的面积

Mo的老师给了他两个矩形,让他求两个矩形的面积并。Mo很忙没时间解决这种小case,请你帮他解决。

输入

输入两行,每行四个整数 x,y,x1,y1 。(x,y) 是矩形左下角,(x1,y1) 是矩形的右上角. (0≤x,y,x1,y1≤1000)。

输出

输出一个整数表示二个矩形的面积并。

#include<bits/stdc++.h>
using namespace std;
int main() {
    int x1, y1, x2, y2;
    int x3, y3, x4, y4;
    cin >> x1 >> y1 >> x2 >> y2;
    cin >> x3 >> y3 >> x4 >> y4;
    int m1, n1, m2, n2;
    m1 = max(x1, x3);
    n1 = max(y1, y3);
    m2 = min(x2, x4);
    n2 = min(y2, y4);
    int sum = (x2 - x1) * (y2 - y1);
    sum += (x4 - x3) * (y4 - y3);
    int rep = 0;
    if(m1 < m2 && n1 < n2) {
        rep = (n2 - n1) * (m2 - m1);
    }
    cout << sum - rep << endl;
    return 0;
}

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转载自blog.csdn.net/Endeavor_G/article/details/88935385
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