生产者/消费者问题
题目描述:
生产者(Productor)将产品交给店员(Clerk),而消费者(Customer)从店员处取走产品,店员一次只能持有固定数量的产品(比如:20),如果生产者试图生产更多的产品,店员会叫生产者停一下,如果店中有空位放产品了再通知生产者继续生产;如果店中没有产品了,店员会告诉消费者等一下,如果店中有产品了再通知消费者来取走产品。
代码:
class Clerk {//店员
int product;
public synchronized void addProduct() {//生产产品
if (product >= 20) {
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else {
product++;
System.out.println(Thread.currentThread().getName() + ":生产了第" + product + "个产品");
notifyAll();
}
}
public synchronized void consumeProduct() {//消费产品
if (product <= 0) {
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
} else {
System.out.println(Thread.currentThread().getName() + ":消费了第" + product + "个产品");
product--;
notifyAll();
}
}
}
class Producer implements Runnable {//生产者
Clerk clerk;
public Producer(Clerk clerk) {
this.clerk = clerk;
}
public void run() {
System.out.println("生产者开始生产产品");
while (true) {
try {
Thread.currentThread().sleep(100);
} catch (InterruptedException e) {
e.printStackTrace();
}
clerk.addProduct();
}
}
}
class Consumer implements Runnable {//消费者
Clerk clerk;
public Consumer(Clerk clerk) {
this.clerk = clerk;
}
public void run() {
System.out.println("消费者开始消费产品");
while (true) {
try {
Thread.currentThread().sleep(10);
} catch (InterruptedException e) {
e.printStackTrace();
}
clerk.consumeProduct();
}
}
}
public class TestProduceConsume {
public static void main(String[] args) {
Clerk clerk = new Clerk();
Producer p1 = new Producer(clerk);
Consumer c1 = new Consumer(clerk);
Thread t1 = new Thread(c1);//消费者1的线程
Thread s1 = new Thread(p1);//生产者1的线程
Thread s2 = new Thread(p1);//生产者2的线程
Thread s3 = new Thread(p1);//生产者3的线程
Thread s4 = new Thread(p1);//生产者4的线程
Thread s5 = new Thread(p1);//生产者5的线程
t1.setName("消费者1");
s1.setName("生产者1");
s2.setName("生产者2");
s3.setName("生产者3");
s4.setName("生产者4");
s5.setName("生产者5");
t1.start();
s1.start();
s2.start();
s3.start();
s4.start();
s5.start();
}
}
程序结果: