Solution
Coding
#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<queue>
#define ll long long
using namespace std;
const int N=1e3+10;
const int M=1e4+100;
const int inf=1e9;
const int maxn=1e4;
int n,A,B,tot,s,t,maxflow,flow,sum,cnt,a[50][50],ver[M],Next[M],edge[M],lin[N],d[N],incf[N],pre[N],cost[M],v[N];
char ch[50];
void add(int x,int y,int z,int val){
ver[++tot]=y;Next[tot]=lin[x];lin[x]=tot;edge[tot]=z;cost[tot]=val;
ver[++tot]=x;Next[tot]=lin[y];lin[y]=tot;edge[tot]=0;cost[tot]=-val;
}
bool spfa(){
queue<int>q;
memset(d,0xcf,sizeof(d));
memset(v,0,sizeof(v));
q.push(s),v[s]=1,d[s]=0;
incf[s]=1e9;
while(q.size()){
int x=q.front();q.pop();v[x]=0;
for(int i=lin[x];i;i=Next[i]){
if(edge[i]){
int y=ver[i];
if(d[y]<d[x]+cost[i]){
d[y]=d[x]+cost[i];
if(!v[y]) v[y]=1,q.push(y);
incf[y]=min(incf[x],edge[i]);
pre[y]=i;
}
}
}
}
if(d[t]==0xcfcfcfcf) return 0;
return 1;
}
void update(){
int x=t;
while(x!=s){
int i=pre[x];
edge[i]-=incf[t];
edge[i^1]+=incf[t];
x=ver[i^1];
}
sum+=incf[t]*d[t];
}
int main(){
while(scanf("%d%d%d",&n,&A,&B)){
if(n==0&&A==0&&B==0) break;
s=0,t=2*n+1;cnt++;
memset(a,-1,sizeof(a));
int dd=0;
for(int i=1;i<=n;++i){
scanf("%s",ch+1);
for(int j=1;j<=n;++j){
if(ch[j]=='C') a[i][j]=1,dd++;
else if(ch[j]=='/') a[i][j]=0;
}
}
int ans;
for(ans=n*n;ans>0;--ans){
memset(lin,0,sizeof(lin));
tot=1;int num=ans*A/B;int temp=0;
for(int i=1;i<=n;++i){
for(int j=1;j<=n;++j){
if(a[i][j]==-1) add(i,n+j,1,1);
else if(a[i][j]==1) add(i,n+j,1,1+maxn),temp++;
}
add(i,i+n,inf,0);add(s,i,num,0);add(i+n,t,num,0);
}
maxflow=flow=0;sum=0;
while(spfa())
update();
sum-=temp*maxn;
if(sum==ans){
printf("Case %d: %d\n",cnt,ans-temp);break;
}else ans=sum+1;
}
if(ans<=0&&dd>0) printf("Case %d: impossible\n",cnt);
else if(ans==0) printf("Case %d: 0\n",cnt);
}
return 0;
}