北邮机试C翻转

这道题，我本来想用上道oj上图像翻转的规律，结果并不成功，最后用了下面的笨办法。

#include<bits/stdc++.h>
using namespace std;
int buf[10][10];
int ans[10][10];
int main(){
	int c1,c2,x,y;
	for(int i=1;i<=5;i++){
		for(int j=1;j<=5;j++){
			scanf("%d",&buf[i][j]);
		}
	}
	for(int i=1;i<=5;i++){
		for(int j=1;j<=5;j++){
			ans[i][j] = buf[i][j];
		}
	}
	
	
	scanf("%d %d %d %d",&c1,&c2,&x,&y);
	if(c1==1&&c2==2){//1 2,顺时针翻转4个数 
		ans[x][y+1] = buf[x][y];
		ans[x+1][y+1] = buf[x][y+1];
		ans[x][y] = buf[x+1][y];
		ans[x+1][y] = buf[x+1][y+1];	
	}
	else if(c1==1&&c2==3){//顺时针反转9个数
		ans[x][y] = buf[x+2][y];
		ans[x][y+1] = buf[x+1][y];
		ans[x][y+2] = buf[x][y];
		ans[x+1][y] = buf[x+2][y+1];
		ans[x+1][y+1] = buf[x+1][y+1];
		ans[x+1][y+2] = buf[x][y+1];
		ans[x+2][y] = buf[x+2][y+2];
		ans[x+2][y+1] = buf[x+1][y+2];
		ans[x+2][y+2] = buf[x][y+2];
		
		
		
		
	}
	else if(c1==2&&c2==2){//逆时针4个数 
		ans[x+1][y] = buf[x][y];
		ans[x][y] = buf[x][y+1];
		ans[x+1][y+1] = buf[x+1][y];
		ans[x][y+1] = buf[x+1][y+1];
		
	} 
	else if(c1==2&&c2==3){//逆时针9个数 
		ans[x][y] = buf[x][y+2];
		ans[x][y+1] = buf[x+1][y+2];
		ans[x][y+2] = buf[x+2][y+2];
		ans[x+1][y] = buf[x][y+1];
		ans[x+1][y+1] = buf[x+1][y+1];
		ans[x+1][y+2] = buf[x+2][y+1];
		ans[x+2][y] = buf[x][y];
		ans[x+2][y+1] = buf[x+1][y];
		ans[x+2][y+2] = buf[x+2][y];
		
	}
	for(int i=1;i<=5;i++){
		for(int j=1;j<=5;j++){
			printf("%d ",ans[i][j]);
		}
		printf("\n");
	}
	return 0;
	
}