数据结构之队列详解

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队列Queue

  • 队列也是一种线性结构
  • 相比数组,队列对应的操作是数组的子集
  • 只能从一端(队尾)添加元素,只能从另一端(队首)取出元素
  • 队列是一种先进先出的数据结构
  • First In First Out(FIFO)

队列的实现

接口Queue:

/**
 * Created by binzhang on 2019/3/17.
 */
public interface Queue<E> {
    int getSize();
    boolean isEmpty();
    void enqueue(E e);
    E dequeue();
    E getFront();
}

实现类ArrayQueue:

/**
 * Created by binzhang on 2019/3/17.
 */
public class ArrayQueue<E> implements Queue<E> {

    private Array<E> array;

    public ArrayQueue(int capacity){
        array = new Array<>(capacity);
    }

    public ArrayQueue(){
        array = new Array<>();
    }

    @Override
    public int getSize() {
        return array.getSize();
    }

    @Override
    public boolean isEmpty() {
        return array.isEmpty();
    }

    public int getCapacity(){
        return array.getCapacity();
    }

    @Override
    public void enqueue(E e) {
        array.addLast(e);
    }

    @Override
    public E dequeue() {
        return array.removeFirst();
    }

    @Override
    public E getFront() {
        return array.getFirst();
    }

    @Override
    public String toString(){
        StringBuilder res = new StringBuilder();
        res.append(String.format("Queue: "));
        res.append('[');
        for (int i = 0 ; i < array.getSize() ; i ++){
            res.append(array.get(i));
            if(i != array.getSize() - 1)
                res.append(", ");
        }
        res.append("] tail");
        return res.toString();
    }

    public static void main(String[] args) {
        ArrayQueue<Integer> queue = new ArrayQueue<>();
        for (int i = 0 ; i < 10 ; i ++){
            queue.enqueue(i);
            System.out.println(queue);
            if (i % 3 == 2){
                queue.dequeue();
                System.out.println(queue);
            }
        }
    }
}

main方法运行结果:

Queue: [0] tail
Queue: [0, 1] tail
Queue: [0, 1, 2] tail
Queue: [1, 2] tail
Queue: [1, 2, 3] tail
Queue: [1, 2, 3, 4] tail
Queue: [1, 2, 3, 4, 5] tail
Queue: [2, 3, 4, 5] tail
Queue: [2, 3, 4, 5, 6] tail
Queue: [2, 3, 4, 5, 6, 7] tail
Queue: [2, 3, 4, 5, 6, 7, 8] tail
Queue: [3, 4, 5, 6, 7, 8] tail
Queue: [3, 4, 5, 6, 7, 8, 9] tail

队列的时间复杂度

ArrayQueue

  • void enqueue(E) O(1)均摊
  • E dequeue() O(n)
  • E front() O(1)
  • int getSize() O(1)
  • boolean isEmpty() O(1)

可以看到数组出列的时间复杂度是O(n)的,所有的元素都要向前挪一位,性能相对是比较低的。
循环队列可以解决这个问题。
循环队列加入了fronttail两个属性。
front==tail时队列为空。
每次入队的时候tail都会向后移动一个单位,当有出队操作时,front也会向后移动一个单位。
在这里插入图片描述

当数据插入到位置7后,tail会回到0位置。
在这里插入图片描述

那么tail是怎么回到0的呢,当我们插入的元素大于队列长度时采用取余的方式来计算
tail = (i + 1)/capacity
这里就是(7+1)/8(8为数组长度)就回到了我们索引为0的位置

注意我们之前定义了front==tail是队列为空的标志,索引当遇到下图情况即tail+1==front(更准确的说是(tail + 1) % c == front)的时候就表明我们的队列是满的了,可以进行扩容了,也就是说循环队列中总会是浪费一个空间的。
在这里插入图片描述

手写一个循环队列:

/**
 * Created by binzhang on 2019/3/17.
 */
public class LoopQueue<E> implements Queue<E> {

    private E[] data;
    private int front, tail;
    private int size;

    public LoopQueue(int capacity){
        // 循环数组是有一个空间浪费的,所以要存储n个要定义空间大小为n+1
        data = (E[])new Object[capacity + 1];
        front = 0;
        tail = 0;
        size = 0;
    }

    public LoopQueue(){
        this(10);
    }

    public int getCapacity(){
        return data.length - 1;
    }

    @Override
    public int getSize() {
        return size;
    }

    @Override
    public boolean isEmpty() {
        return front == tail;
    }

    @Override
    public void enqueue(E e) {
        if ((tail + 1) % data.length == front)
            resize(getCapacity() * 2);
        data[tail] = e;
        tail = (tail + 1) % data.length;
        size ++;
    }

    private void resize(int newCapacity){
        E[] newData = (E[])new Object[newCapacity + 1];
        for (int i = 0 ; i < size ; i ++)
            newData[i] = data[(i + front) % data.length];
        data = newData;
        front = 0;
        tail = size;
    }

    @Override
    public E dequeue() {
        if (isEmpty())
            throw new IllegalArgumentException("Cannot dequeue from an empty queue.");
        E ret = data[front];
        data[front] = null;
        front = (front + 1) % data.length;
        size --;
        if (size == getCapacity() / 4 && getCapacity() / 2 != 0)
            resize(getCapacity() / 2);
        return ret;
    }

    @Override
    public E getFront() {
        if (isEmpty())
            throw new IllegalArgumentException("Cannot dequeue from an empty queue.");
        return data[front];
    }

    @Override
    public String toString(){
        StringBuilder res = new StringBuilder();
        res.append(String.format("Queue: size = %d, capacity = %d\n", size, getCapacity()));
        res.append("front [");
        for (int i = front ; i != tail ; i = (i + 1) % data.length){
            res.append(data[i]);
            if((i + 1) % data.length != tail)
                res.append(", ");
        }
        res.append("] tail");
        return res.toString();
    }

    public static void main(String[] args) {
        LoopQueue<Integer> loopQueue = new LoopQueue<>();
        for (int i = 0 ; i < 10 ; i ++){
            loopQueue.enqueue(i);
            System.out.println(loopQueue);
            if (i % 3 == 2){
                loopQueue.dequeue();
                System.out.println(loopQueue);
            }
        }

    }
}

输出:

Queue: size = 1, capacity = 10
front [0] tail
Queue: size = 2, capacity = 10
front [0, 1] tail
Queue: size = 3, capacity = 10
front [0, 1, 2] tail
Queue: size = 2, capacity = 5
front [1, 2] tail
Queue: size = 3, capacity = 5
front [1, 2, 3] tail
Queue: size = 4, capacity = 5
front [1, 2, 3, 4] tail
Queue: size = 5, capacity = 5
front [1, 2, 3, 4, 5] tail
Queue: size = 4, capacity = 5
front [2, 3, 4, 5] tail
Queue: size = 5, capacity = 5
front [2, 3, 4, 5, 6] tail
Queue: size = 6, capacity = 10
front [2, 3, 4, 5, 6, 7] tail
Queue: size = 7, capacity = 10
front [2, 3, 4, 5, 6, 7, 8] tail
Queue: size = 6, capacity = 10
front [3, 4, 5, 6, 7, 8] tail
Queue: size = 7, capacity = 10
front [3, 4, 5, 6, 7, 8, 9] tail

循环队列出列的时间复杂度变为O(1)

循环队列的时间复杂度

LoopQueue

  • void enqueue(E) O(1)均摊
  • E dequeue() O(1) 均摊
  • E front() O(1)
  • int getSize() O(1)
  • boolean isEmpty() O(1)

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转载自blog.csdn.net/qq_24095055/article/details/88623037
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