python 倒计时灯管

版权声明： https://blog.csdn.net/lyw_321/article/details/79886730

根据老师的代码 稍微改了下

#SevenDigitsDrawV1.py
import turtle
turtle.speed(0)         #改变速度
turtle.hideturtle()     #隐藏小海龟
def drawLine(draw):   #绘制单段数码管
    turtle.pendown() if draw else turtle.penup()
    turtle.fd(40)
    turtle.right(90)
def drawDigit(digit): #根据数字绘制七段数码管
    drawLine(True) if digit in [2,3,4,5,6,8,9] else drawLine(False)
    drawLine(True) if digit in [0,1,3,4,5,6,7,8,9] else drawLine(False)
    drawLine(True) if digit in [0,2,3,5,6,8,9] else drawLine(False)
    drawLine(True) if digit in [0,2,6,8] else drawLine(False)
    turtle.left(90)
    drawLine(True) if digit in [0,4,5,6,8,9] else drawLine(False)
    drawLine(True) if digit in [0,2,3,5,6,7,8,9] else drawLine(False)
    drawLine(True) if digit in [0,1,2,3,4,7,8,9] else drawLine(False)
    turtle.left(180)
    turtle.penup()
    turtle.fd(20) 
def drawDate(date):  #获得要输出的数字
    for i in date:
        drawDigit(eval(i))  #通过eval()函数将数字变为整数
def main():
    turtle.setup(800, 350, 200, 200)
    turtle.penup()
    turtle.fd(-300)
    turtle.pensize(5)
    a=input('请输入你想要倒计时的数字:')
    while eval(a)+1:                #保证0也能画出
        drawDate(a)       
        turtle.fd(-(60)*len(a))     #根据数字位数回到起始点
        if a!='0':
            turtle.clear()          #清空笔迹
        a=str((int(a)-1))           #减一    
    turtle.done()
main()