题目描述
Given an n-ary tree, return the level order traversal of its nodes’ values. (ie, from left to right, level by level).
For example, given a 3-ary tree:
方法思路
class Solution {
//Runtime: 5 ms, faster than 58.99%
//Memory Usage: 48.4 MB, less than 48.55%
public List<List<Integer>> levelOrder(Node root) {
List<List<Integer>> ans = new ArrayList<>();
if(root == null) return ans;
Queue<Node> queue = new LinkedList<>();
queue.offer(root);
List<Integer> l = new ArrayList<>();
l.add(root.val);
ans.add(l);
while(!queue.isEmpty()){
int size = queue.size();
while(size-- > 0){
Node node = queue.poll();
if(node.children != null)
for(Node n : node.children)
queue.offer(n);
}
if(queue.size() > 0){
List<Integer> list = new ArrayList<>();
for(Node node : queue)
list.add(node.val);
ans.add(list);
}
}
return ans;
}
}