【Codeforces 466B】Wonder Room

【链接】 我是链接,点我呀:)
【题意】


让你把长为a,宽为b的房间扩大(长和宽都能扩大)。
使得它的面积达到6*n
问你最小的能满足要求的面积是多少
输出对应的a和b

【题解】


假设a< b
然后我们枚举新的a(较小的哪一个)为newa
newa只需要枚举到ceil(sqrt(6n))就好
因为如果newa>ceil(sqrt(6
n))的话
得到的newb = ceil(sqrt(6n))/newa
newb肯定是小于等于ceil(sqrt(6
n))的
而我们之前newa已经枚举过这种情况了,所以不可能得到更优解。
newb判断一下是不是大于等于b就好
(注意我们在枚举newa的时候,得到的newb ,也会满足newa<=newb)
(判断的时候肯定是小的和小的比,大的和大的比,所以一开始的时候,显然小的值放在a,大的值放在b,然后枚举小的值一直增大)

【代码】

import java.io.*;
import java.util.*;

public class Main {
    
    
    static InputReader in;
    static PrintWriter out;
        
    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }
    
    static int N = 50000;
    static class Task{
        
        long n,a,b;
        public void solve(InputReader in,PrintWriter out) {
            n = in.nextLong();a = in.nextLong();b = in.nextLong();
            if (a*b>=6*n) {
                out.println(a*b);
                out.println(a+" "+b);
                return;
            }
            long temp = (long)Math.sqrt(6*n);
            if (temp*temp<6*n) temp++;
            long ans = (long)(1e18)+100;
            long temp1 = 0,temp2 =0;
            boolean f = false;
            if (a>b) {
                long temp3 = a;a = b;b = temp3;
                f =true;
            }
            
            for (long newa = a;newa <=temp;newa++) {
                long newb = (6*n)/newa;
                if (newa*newb<(6*n)) newb++;
                
                if (newb < b) continue;
                if (newa*newb>=6*n && newa*newb<ans) {
                    ans = Math.min(ans, newa*newb);
                    temp1 = newa;temp2 = newb;
                }
            }
            if (f) {
                long temp3 = temp1;temp1 = temp2;temp2 = temp3;
            }
            out.println(ans);
            out.println(temp1+" "+temp2);
        }
    }

    

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;
        
        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }
        
        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
        
        public long nextLong() {
            return Long.parseLong(next());
        }
    }
}

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转载自www.cnblogs.com/AWCXV/p/10505402.html
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