[leetcode]974. Subarray Sums Divisible by K
Analysis
努力工作哇—— [每天刷题并不难0.0]
Given an array A of integers, return the number of (contiguous, non-empty) subarrays that have a sum divisible by K.
Explanation:
https://leetcode.com/problems/subarray-sums-divisible-by-k/discuss/217985/JavaC%2B%2B-Count-the-Remainder
The key point is :we just have to see if running total mod k is equal to any previous running total mod k
Implement
class Solution {
public:
int subarraysDivByK(vector<int>& A, int K) {
vector<int> count(K);
int pre = 0;
int res = 0;
count[0] = 1;
for(int a:A){
pre = (pre+a%K+K)%K;
res += count[pre]++;
}
return res;
}
};