#12 Integer to Roman

Description

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.

Symbol    Value
I               1
V              5
X              10
L               50
C              100
D               500
M              1000

For example, two is written as II in Roman numeral, just two one’s added together. Twelve is written as, XII, which is simply X + II. The number twenty seven is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

I can be placed before V (5) and X (10) to make 4 and 9.
X can be placed before L (50) and C (100) to make 40 and 90.
C can be placed before D (500) and M (1000) to make 400 and 900.

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999.

Examples

Example 1:

Input: 3
Output: “III”

Example2:

Input: 4
Output: “IV”

Example3:

Input: 9
Output: “IX”

Example 4:

Input: 58
Output: “LVIII”
Explanation: L = 50, V = 5, III = 3.

Example 5:

Input: 1994
Output: “MCMXCIV”
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

解题思路

题目不难(主要没有solution我也不知道有没有什么更好的方法QuQ
我用的是穷举,一层一层下放嘛

class Solution {
    public String intToRoman(int num) {
        int[] n = new int[13];
        n[0] = num / 1000;
        num = num % 1000;
        n[1] = num / 900;
        num = num % 900;
        
        n[2] = num / 500;
        num = num % 500;
        n[3] = num / 400;
        num = num % 400;
        
        n[4] = num / 100;
        num = num % 100;
        n[5] = num / 90;
        num = num % 90;
        
        n[6] = num / 50;
        num = num % 50;
        n[7] = num / 40;
        num = num % 40;
        
        n[8] = num / 10;
        num = num % 10;
        n[9] = num / 9;
        num = num % 9;
        
        n[10] = num / 5;
        num = num % 5;
        n[11] = num / 4;
        num = num % 4;
        
        n[12] = num;
        String temp = "";
        String[] c = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
        for(int i = 0; i < 13; i++){
            for(int j = 0; j < n[i]; j++){
                temp += c[i];
            }
        }
        return temp;
    }
}

代码很长,但是速度意外的还好?

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转载自blog.csdn.net/YY_Tina/article/details/86570114