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numpy
np.hypot(dx, dy)返回的欧几里德范数 sqrt(xx + yy).
官方解释：
numpy.hypot(x1, x2, /, out=None, *, where=True, casting=‘same_kind’, order=‘K’, dtype=None, subok=True[, signature, extobj]) = <ufunc ‘hypot’> .
Given the “legs” of a right triangle, return its hypotenuse.
Equivalent to sqrt(x12 + x22), element-wise. If x1 or x2 is scalar_like (i.e., unambiguously cast-able to a scalar type), it is broadcast for use with each element of the other argument. (See Examples)