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题目链接:https://www.nowcoder.com/acm/contest/201/L
今天在牛客网上过国庆节的时候发现一个有点意思的最短路问题,链接在上面,代码在下面:
#include<bits/stdc++.h>
using namespace std;
int a,b,c1,c2;
const int INF =1e8;
struct node{
int x,y,r;
}cir[1005];
int book[1005];
double distance1(node A,node B){
double dis=sqrt(pow(A.x-B.x,2)+pow(A.y-B.y,2));
return max(dis-A.r-B.r,0.0);
}
double distance2(node A,int c){
double dis=abs(a*A.x+b*A.y+c)/sqrt(pow(a,2)+pow(b,2));
return max(dis-A.r,0.0);
}
double dis[1005];
int main()
{
int n;
cin>>n>>a>>b>>c1>>c2;
memset(dis,1e5,sizeof(dis));
memset(book,0,sizeof(book));
for(int i=0;i<n;i++){
scanf("%d%d%d",&cir[i].x,&cir[i].y,&cir[i].r);
}
for(int i=0;i<n;i++){
dis[i]=distance2(cir[i],c1);
}
dis[n]=abs(c1-c2)/sqrt(pow(a,2)+pow(b,2));
int u;
for (int i=1;i<=n;i++){
int min=INF;
for (int j=0;j<n;j++){
if (book[j]==0 && dis[j]<min){ //找出未确定最短路径的距离源点最近的点
min=dis[j];
u=j;
}
}
book[u]=1; //标记u点 说明到u点的最短路径已经确定
for (int v=0;v<n;v++){
if (dis[v]>dis[u]+distance1(cir[u],cir[v]))
dis[v]=dis[u]+distance1(cir[u],cir[v]);
}
if(dis[n]>dis[u]+distance2(cir[u],c2))
dis[n]=dis[u]+distance2(cir[u],c2);
}
printf("%.6lf",dis[n]);
}