LeetCode-132-Palindrome Partitioning II

算法描述：

Given a string s, partition s such that every substring of the partition is a palindrome.

Return the minimum cuts needed for a palindrome partitioning of s.

Example:

Input: "aab"
Output: 1
Explanation: The palindrome partitioning ["aa","b"] could be produced using 1 cut.

解题思路：动态规划题。除了判断回文的辅助数组之外，还需要额外的数组记录最小分割次数。

    int minCut(string s) {
        if(s.size() < 2) return 0;
        vector<vector<bool>> dp(s.size(), vector<bool>(s.size(),0));
        vector<int> count(s.size(),0);
        for(int i=s.size()-1; i >=0; i--){
            dp[i][i] = true;
            count[i]=s.size()-1-i;
            for(int j=i; j < s.size(); j++){
                if(s[i]==s[j] && (j-i < 2 ||  dp[i+1][j-1])){
                    dp[i][j]=true;
                    if(j==s.size()-1) count[i]=0;
                    else
                        count[i] = min(count[i],1+count[j+1]);
                    
                }
            }
        }
        return count[0];
    }