PAT A1028

1028 List Sorting （25 分）

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:

Each input file contains one test case. For each case, the first line contains two integers N (≤10​5​​) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1:

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1:

000001 Zoe 60
000007 James 85
000010 Amy 90

Sample Input 2:

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2:

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3:

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3:

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

 题意：

模仿 Excel 软件列排序功能，给出 n 行数据，和指定排列的列号 c，按照排序规则进行排列

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
struct Student{
	char id[8];
	char name[10];
	int score;
}stu[100010];
bool cmp1(Student a, Student b){
	return strcmp(a.id, b.id) < 0;
}
bool cmp2(Student a, Student b){
	if(strcmp(a.name, b.name) != 0)
		return strcmp(a.name, b.name) < 0;
	else
		return strcmp(a.id, b.id) < 0;
}
bool cmp3(Student a, Student b){
	if(a.score != b.score)
		return a.score < b.score;
	else
		return strcmp(a.id, b.id) < 0;
}
int main(){
	int n, c;
	scanf("%d%d", &n, &c);
	for(int i = 0; i < n; i++){
		scanf("%s%s%d", stu[i].id, stu[i].name, &stu[i].score);
	}
	if(c == 1)
		sort(stu, stu+n, cmp1);		
	else if(c == 2)
		sort(stu, stu+n, cmp2);
	else if(c == 3)
		sort(stu, stu+n, cmp3);
	for(int i = 0; i < n; i++){
		printf("%s %s %d\n", stu[i].id, stu[i].name, stu[i].score);
	}
	return 0;
}