这道题在《算法竞赛入门经典》（第2版）上有点小问题，不能AC，稍稍改了guess函数部分就OK
In “Hangman Judge,” you are to write a program that judges a series of Hangman games. For each
game, the answer to the puzzle is given as well as the guesses. Rules are the same as the classic game
of hangman, and are given as follows:
1.
The contestant tries to solve to puzzle by guessing one letter at a time.
2.
Every time a guess is correct, all the characters in the word that match the guess will be “turned
over.” For example, if your guess is ‘o’ and the word is “book”, then both ‘o’s in the solution will
be counted as “solved”.
3.
Every time a wrong guess is made, a stroke will be added to the drawing of a hangman, which
needs 7 strokes to complete. Each unique wrong guess only counts against the contestant once.
______
| |
| O
| /|\
| |
| / \
__|_
| |______
|_________|
4.
If the drawing of the hangman is completed before the contestant has successfully guessed all the
characters of the word, the contestant loses.
5.
If the contestant has guessed all the characters of the word before the drawing is complete, the
contestant wins the game.
6.
If the contestant does not guess enough letters to either win or lose, the contestant chickens out.
Your task as the “Hangman Judge” is to determine, for each game, whether the contestant wins,
loses, or fails to finish a game.
Input
Your program will be given a series of inputs regarding the status of a game. All input will be in lower
case. The first line of each section will contain a number to indicate which round of the game is being
played; the next line will be the solution to the puzzle; the last line is a sequence of the guesses made
by the contestant. A round number of ‘
-1
’ would indicate the end of all games (and input).
Output
The output of your program is to indicate which round of the game the contestant is currently playing
as well as the result of the game. There are three possible results:
You win.
You lose.
You chickened out.
Sample Input
1
cheese
chese
2
cheese
abcdefg
3
cheese
abcdefgij
-1
SampSample Output
Round 1
You win.
Round 2
You chickened out.
Round 3
You lose.
AC过的：
#include<stdio.h>
#include<string.h> #define maxn 100 int loc, chance; //loc是还需要猜几个位置，chance是还有多少次机会 char s1[maxn], s2[maxn]; //s1代表计算机想的单词，s2代表玩家的猜测 int win, lose; //根据win和lose的0和1状态判断输赢 void guess(char ch) { int bad = 1; //猜错标志 for (int i = 0; i < strlen(s1); i++) //遍历计算机给的单词 if (s1[i] == ch) {//如果猜中了一个字母 if (--loc == 0) {//如果都猜中了 win = 1; break; } s1[i] = ' '; //猜过的字母再猜一次就算猜错，所以这里猜过的字母用空格来替换 bad = 0; } if (bad) if (--chance == 0) lose = 1; } int main() { int Round; //回合数 while (scanf("%d%s%s", &Round, s1, s2)==3&&Round!=-1) { printf("Round %d\n", Round); //先打印回合数 win = lose = 0; //每一组新的数据之前初始化 loc = strlen(s1); chance = 7; //最多能猜错6次，因此共有7次机会，第7次不能再错 for (int i = 0; i < strlen(s2); i++) { guess(s2[i]); //猜一个字母 if (win || lose||chance==0) break; //判断状态 } if (win) printf("You win.\n"); else if(lose&&!chance) printf("You lose.\n"); //只有chance用完，也即为0时才能算lose else printf("You chickened out.\n"); //chance次数不为0时，算放弃 } return 0; }