UVA489 - Hangman Judge【紫书例题4.2】

题意：就是给出一个字符串，让你去一个一个猜测，相同字母算一次，如果是之前猜过的也算错，如果你在错7次前猜对就算你赢，文章中是LRJ的例题代码。

#include<stdio.h>
#include<string.h>
#define maxn 100
int left, chance;
char s[maxn], s2[maxn];
int win, lose;

void guess(char ch) {
  int bad = 1;
  for(int i = 0; i < strlen(s); i++)
    if(s[i] == ch) { left--; s[i] = ' '; bad = 0; }
  if(bad) --chance;
  if(!chance) lose = 1;
  if(!left) win = 1;
}

int main() {
  int rnd;
  while(scanf("%d%s%s", &rnd, s, s2) == 3 && rnd != -1) {
    printf("Round %d\n", rnd);
    win = lose = 0;
    left = strlen(s);
    chance = 7;
    for(int i = 0; i < strlen(s2); i++) {
      guess(s2[i]);
      if(win || lose) break;
    }
    if(win) printf("You win.\n");
    else if(lose) printf("You lose.\n");
    else printf("You chickened out.\n");
  }
  return 0;
}