SpringMVC接收页面表单参数

一个普通的表单。

　　表单的代码如下：

<%@ page language="java" pageEncoding="UTF-8"%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title><script type="text/javascript">    
//添加用户    
function addUser() {        
var form = document.forms[0];        
form.action = "${pageContext.request.contextPath}/user/addUser1";       
//form.action = "${pageContext.request.contextPath}/user/addUser2";        
//form.action = "${pageContext.request.contextPath}/user/addUser3";        
form.method = "post";        
form.submit();    
}
</script>
</head>
<body>    
<form>        
<table>            
<tr>                
<td>账号</td>                
<td><input type="text" name="userName"></td>         
</tr>           
<tr>                
<td>密码</td>
<td><input type="password" name="password"></td>
</tr>           
<tr>                
<td>&nbsp;</td>                
<td><input type="button" value="提交" onclick="addUser()">               
</td>            
</tr>       
</table>    
</form>
</body>
</html>

　　1、直接把表单的参数写在Controller相应的方法的形参中

@RequestMapping("/addUser1")    
public String addUser1(String userName,String password) {        
	System.out.println("userName is:"+userName);        
	System.out.println("password is:"+password);        
	return "/user/success";    
}

　　2、通过HttpServletRequest接收

@RequestMapping("/addUser2")    
public String addUser2(HttpServletRequest request) {        
	String userName = request.getParameter("userName");        
	String password = request.getParameter("password");        
	System.out.println("userName is:"+userName);        
	System.out.println("password is:"+password);        
	return "/user/success";    
}

　　3、通过一个bean来接收

　　　　1）建立一个和表单中参数对应的bean

public class User {        
	private String userName;        
	private String password;    
	public String getUserName() {        
		return userName;    
	}    
	public void setUserName(String userName) {        
		this.userName = userName;   
	}    
	public String getPassword() {        
		return password;    
	}    
	public void setPassword(String password) {        
		this.password = password;    
	}
}

　　　　2）用这个bean来封装接收的参数

@RequestMapping("/addUser3")    
public String addUser3(User user) {        
	System.out.println("userName is:"+user.getUserName());        
	System.out.println("password is:"+user.getPassword());        
	return "/user/success";    
}

　　4、通过json数据接收

<%@ page language="java" pageEncoding="UTF-8"%>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title>
<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js">
</script><script type="text/javascript">    
$(document).ready(function(){        
	$("#button_submit").click(function(){            
	var name = $("#userName").val();            
	var pass = $("#password").val();            
            
	var user = {userName:name,password:pass};//拼装成json格式 
         $.ajax({                
		type:"POST",                
		url:"${pageContext.request.contextPath}/user/addUser4", 
                data:user,                
 		success:function(data){                    
			alert("成功"); 
                },                
		error:function(e) {                    
			alert("出错："+e);                
		}            
	});        
	});    
	});
</script>
</head>
<body>    
<form>        
<table>            
<tr><td>账号</td>                
    <td><input type="text" id="userName" name="userName"></td>
</tr>            
<tr>
    <td>密码</td>
    <td><input type="password" id="password" name="password"></td>            
</tr>            
<tr>
    <td>&nbsp;</td> 
    <td><input type="button" id="button_submit" value="提交"></td>            
</tr>        
</table>   
</form>
</body>
</html>

　　依然可以使用bean来接收json数据

@RequestMapping("/addUser4")    
public String addUser4(User user) {        
	System.out.println("userName is:"+user.getUserName());        
	System.out.println("password is:"+user.getPassword());        
	return "/user/success";   
}

　　5、使用jQuery的serializeArray() 方法序列化表单元素

　　　　如果表单元素很多，手工拼装成json数据非常麻烦，可以使用jQuery提供的serializeArray()方法序列化表单元素，返回json数据结构数据。　　

<%@ page language="java" pageEncoding="UTF-8"%
<html><head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Add User</title>
<script type="text/javascript" src="${pageContext.request.contextPath}/resource/script/jquery-1.9.1.min.js">
</script><script type="text/javascript">    
$(document).ready(function(){        
$("#button_submit").click(function(){                        
//序列化表单元素，返回json数据            
var params = $("#userForm").serializeArray();                        
//也可以把表单之外的元素按照name value的格式存进来            
//params.push({name:"hello",value:"man"});                        
$.ajax({                
type:"POST",                
url:"${pageContext.request.contextPath}/user/addUser5",                
data:params,                
success:function(data){                    
alert("成功");                
},                
error:function(e) {                    
alert("出错："+e);                
}            
});        
});    
});
</script>
</head>
<body>    
<form id="userForm">        
<table>            
<tr>                <td>账号</td>                
<td><input type="text" id="userName" name="userName"></td>            
</tr>            
<tr><td>密码</td>
<td><input type="password" id="password" name="password"></td>            
</tr>            
<tr> <td>&nbsp;</td>
<td> <input type="button" id="button_submit" value="提交"> </td></tr>        
</table>    
</form>
</body>
</html>

　　依然可以使用bean来接收json数据：

@RequestMapping("/addUser5")    
public String addUser5(User user) {        
System.out.println("userName is:"+user.getUserName());        
System.out.println("password is:"+user.getPassword());        
return "/user/success";    
}

SpringMVC接收页面表单参数

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