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0x00 介绍
培根密码实际上就是一种替换密码，根据所给表一一对应转换即可加密解密
它的特殊之处在于：可以通过不明显的特征来隐藏密码信息，比如大小写、正斜体等，只要两个不同的属性，密码即可隐藏
0x01 代码实现
脚本很简单，就是建立对应关系，对密文，或者明文进行相应的替换即可
需要注意的是输入的都应该是全小写字母或全大写字母，在脚本里也有说明
python脚本如下：
# coding:utf8import realphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']first_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb","bbaaa","bbaab"]second_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","baabb","babaa","babab","babba","babbb"]def encode(): upper_flag = False # 用于判断输入是否为大写 string = raw_input("please input string to encode:\n") if string.isupper(): upper_flag = True string = string.lower() e_string1 = "" e_string2 = "" for index in string: for i in range(0,26): if index == alphabet[i]: e_string1 += first_cipher[i] e_string2 += second_cipher[i] break if upper_flag: e_string1 = e_string1.upper() e_string2 = e_string2.upper() print "first encode method result is:\n"+e_string1 print "second encode method result is:\n"+e_string2 returndef decode(): upper_flag = False # 用于判断输入是否为大写 e_string = raw_input("please input string to decode:\n") if e_string.isupper(): upper_flag = True e_string = e_string.lower() e_array = re.findall(".{5}",e_string) d_string1 = "" d_string2 = "" for index in e_array: for i in range(0,26): if index == first_cipher[i]: d_string1 += alphabet[i] if index == second_cipher[i]: d_string2 += alphabet[i] if upper_flag: d_string1 = d_string1.upper() d_string2 = d_string2.upper() print "first decode method result is:\n"+d_string1 print "second decode method result is:\n"+d_string2 returnif __name__ == '__main__': print "\t\tcoding by qux" while True: print "\t*******Bacon Encode_Decode System*******" print "input should be only lowercase or uppercase,cipher just include a,b(or A,B)" print "1.encode\n2.decode\n3.exit" s_number = raw_input("please input number to choose\n") if s_number == "1": encode() raw_input() elif s_number == "2": decode() raw_input() elif s_number == "3": break else: continue
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0x02 不足
脚本的提示是英语，如果想改的话，在每个输出的地方把输出的字符串编码转一下就可以了，比如: print("你好".decode("utf-8").encode("gbk"))
感觉没什么必要……
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