python基础——字典综合练习

1.输出字典内数组平均值
a={'name':'Tom','age':20,'address':'北京','score':[89,99,78,95]}

a = {'name': 'Tom', 'age': 20, 'address': '北京', 'score': [89, 99, 78, 95]}

b = a['score']  # 找出'score'对应的值，定义为b

sum = 0

for i in b:  # 用for循环求出和

    sum += i

print(sum / len(b))  # 用和除以列表长度

输出结果： 90.25

2.输出字典003的所有key,value
a={'001':{'name':'张三','age':20,'address':'北京','score':88},
'002':{'name':'李四','age':20,'address':'北京','score':78},
'003':{'name':'王五','age':20,'address':'北京','score':95},
'004':{'name':'小明','age':20,'address':'北京','score':90}}

a={'001':{'name':'张三','age':20,'address':'北京','score':88},
   '002':{'name':'李四','age':20,'address':'北京','score':78},
   '003':{'name':'王五','age':20,'address':'北京','score':95},
   '004':{'name':'小明','age':20,'address':'北京','score':90}}

b = a['003']         # 找到'003'所对应的字典

for key,value in b.items():   # b.items()是列表套元组的形式

    print(key,'-----',value)

输出结果：name ----- 王五
age ----- 20
address ----- 北京
score ----- 95

3.给所有北京人加100000住房补贴
a={'001':{'name':'张三','age':20,'address':'北京','score':88},
'002':{'name':'李四','age':20,'address':'山东','score':78},
'003':{'name':'王五','age':20,'address':'北京','score':95},
'004':{'name':'小明','age':20,'address':'河北','score':90}

a = {'001': {'name': '张三', 'age': 20, 'address': '北京', 'score': 88},
     '002': {'name': '李四', 'age': 20, 'address': '山东', 'score': 78},
     '003': {'name': '王五', 'age': 20, 'address': '北京', 'score': 95},
     '004': {'name': '小明', 'age': 20, 'address': '河北', 'score': 90}}

for i in a.values():
    
    if i['address'] == '北京':  # 判断出那些字典中有北京
        
        i['housing add'] = 10000  # 向有北京的字典中加入
   
     print(i)

输出结果：

{'name': '张三', 'age': 20, 'address': '北京', 'score': 88, 'housing add': 10000}
{'name': '李四', 'age': 20, 'address': '山东', 'score': 78}
{'name': '王五', 'age': 20, 'address': '北京', 'score': 95, 'housing add': 10000}
{'name': '小明', 'age': 20, 'address': '河北', 'score': 90}

4.输出二维字典最大age和最小age

a={ '001':{'name':"李四",'age':28,'address':"山东",'score':88},
'002':{'name':"张三",'age':18,'address':"北京",'score':98},
'003':{'name':"小明",'age':48,'address':"河北",'score':90},
'004':{'name':"王五",'age':38,'address':"北京",'score':78}
}

a = {'001': {'name': "李四", 'age': 28, 'address': "山东", 'score': 88},
     '002': {'name': "张三", 'age': 18, 'address': "北京", 'score': 98},
     '003': {'name': "小明", 'age': 48, 'address': "河北", 'score': 90},
     '004': {'name': "王五", 'age': 38, 'address': "北京", 'score': 78}
     }

max = a['001']['age']  # 定义第一个键值对是最大和最小的。

min = a['001']['age']

for i in a.values():
    
    if i['age'] > max:  # 将每个找到的的值与max和min比较
        
        max = i['age']
    
    elif i['age'] < min:
       
        min = i['age']

print('max:{}\nmin:{}'.format(max, min))

输出结果： max:48

min:18

python基础——字典综合练习

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