截取URL地址栏的请求参数(get请求)(?之后的内容)

版权声明:毒牙工作室 https://blog.csdn.net/qq_35023116/article/details/86131692
// 截取 ? 之后的内容
const subParam = (param) => {
    const pattern = /(\w+)=(\w+)/ig;
    let paramObj = {}
    param ? param.url.replace(pattern, (a, b, c) => {
        paramObj[b] = c;
    }) : {...param};
    return paramObj
};

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转载自blog.csdn.net/qq_35023116/article/details/86131692
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