hihocoder1736 最大的K-偏差排列

思路：

容易写错的贪心题。

实现：

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int n, k;
 6     while (cin >> n >> k)
 7     {
 8         int tot = n / (2 * k) * 2 * k;
 9         bool flg = false;
10         for (int i = 0; i < tot; i++)
11         {
12             if (i % k == 0) flg = !flg;
13             cout << (flg ? i + 1 + k : i + 1 - k) << " ";
14         }
15         if (n - tot <= k)
16         {
17             for (int i = n; i > tot; i--) cout << i << " ";
18         }
19         else
20         {
21             for (int i = tot; i < n - k; i++) cout << i + 1 + k << " ";
22             for (int i = tot + k - 1; i >= n - k; i--) cout << i + 1 << " ";
23             for (int i = tot + k; i < n; i++) cout << i + 1 - k << " ";
24         }
25         cout << endl;
26     }
27     return 0;
28 }