Ricky’s RealDan’s Ricky

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https://ac.nowcoder.com/acm/contest/322/H

题解:

当且仅当n==1,a【1】为偶数才能赢。。。。。。

/*
*@Author:   STZG
*@Language: C++
*/
#include <bits/stdc++.h>
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<string>
#include<vector>
#include<bitset>
#include<queue>
#include<deque>
#include<stack>
#include<cmath>
#include<list>
#include<map>
#include<set>
//#define DEBUG
#define RI register int
using namespace std;
typedef long long ll;
//typedef __int128 lll;
const int N=100000+10;
const int MOD=1e9+7;
const double PI = acos(-1.0);
const double EXP = 1E-8;
const int INF = 0x3f3f3f3f;
int t,n,m,k,q,ans;
int a[N];
char str;
int main()
{
#ifdef DEBUG
	freopen("input.in", "r", stdin);
	//freopen("output.out", "w", stdout);
#endif
    scanf("%d",&t);
    while(t--){
        scanf("%d",&n);
        ll sum=0;
        for(int i=1;i<=n;i++){
            scanf("%d",&a[i]);
            if(a[i]%2==0){
                sum++;
            }
            //sum+=a[i];
        }
        if(sum==1){
            cout << "Ricky is Winner" << endl;
        }else{
            cout << "RealDan is Winner" << endl;

        }
    }
    //cout << "Hello world!" << endl;
    return 0;
}

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转载自blog.csdn.net/weixin_43272781/article/details/85398859
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