绘制钻石图案。将一圆周进行n等分,然后将所有的等分用直线连接,构成图案。

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/tingary/article/details/72473038

绘制钻石图案。将一圆周进行n等分,然后将所有的等分用直线连接,构成图案。
例如:
n=8
q =2*p/n
X=2*r*cos(q)
Y=r*sin(q)


#include <GL/glut.h>

#include <math.h>

#include <stdlib.h>

#include <stdio.h>

#define pi 3.14159265

int n=8;

int R=200,CX=250,CY=250;

int *point;

void initGraph(void);

void drawCircle(int cx, int cy, int r);

void display(void);

void drawLine(int x1, int y1, int x2, int y2);

void main(int argc, char **argv){

     float w,wi;

     glutInit(&argc,argv);

     glutInitDisplayMode(GLUT_SINGLE|GLUT_RGB) ; 

     glutInitWindowSize(500,500);

     glutCreateWindow("n阶钻石图案");

     initGraph();

point=(int*)malloc(sizeof(int)*n*2);//申请存储空间

w=2*pi/n;

wi=w/2;

for(int i=0;i<2*n;i+=2){

point[i]=(int)(CX+R*cos(wi));

point[i+1]=(int)(CY+R*sin(wi));

wi+=w;

}

    glutDisplayFunc(display); 

    glutMainLoop();

    if(point!=NULL)free(point);//释放存储空间

}

void initGraph (void){

    glClearColor(0.0,0.0,0.0,0.0);

    gluOrtho2D(0.0,500.0,0.0,500.0);//窗口坐标左下角(0,0), 右上角(500,500)

}

void display(void){

     glClear(GL_COLOR_BUFFER_BIT) ; 

     glColor3f(1.0, 1.0, 0.0) ; 

     for(int i=0;i<2*n-2;i+=2){

          for(int j=i+2;j<2*n;j+=2){

              drawLine(point[i],point[i+1],point[j],point[j+1]);  

          }

    }

}

 

void drawLine(int x1, int y1, int x2, int y2) {

    glBegin(GL_LINES);

    glVertex2d(x1, y1);

    glVertex2d(x2, y2);

    glEnd();

    glFlush() ;

}




猜你喜欢

转载自blog.csdn.net/tingary/article/details/72473038
今日推荐