select t.INST_ID,
count(*) count_all,
sum(case
when t.STATUS = 'ACTIVE' then
1
else
0
end) count_active
from gv$session t
group by t.INST_ID
order by t.inst_id;
查看oracle连接数以及活跃连接数
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转载自blog.csdn.net/dboy_willow/article/details/81002133
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