简单的api实现以及动态函数调用

实现一个简单的api功能，环境python2.7

1. 请求方法:curl http://ip:8000/?name={api中的方法名}|python -m json.tool
2. 只需编写api的方法即可

#!/usr/bin/env python
#coding:utf-8
import json
import api
from wsgiref.util import setup_testing_defaults
from wsgiref.simple_server import make_server

def simple_app(environ, start_response):
    setup_testing_defaults(environ)

    status = '200 OK'
    headers = [('Content-type', 'text/plain;charset=UTF-8')]

    start_response(status, headers)
    
    params = parse_qs(environ['QUERY_STRING'])
    name = params.get('name')[0]
    #判断api中是否有name的方法，有就调用并返回
    if hasattr('api',name):
          dic = eval('api.'+name)()
    else:
          dic = {'resdec':'No method %s'%(name)}
    return [json.dumps(dic)]        
if __name__ == '__main__':
    httpd = make_server('', 8000, simple_app)
    print "Serving on port 8000..."
    httpd.serve_forever()