leetcode961

class Solution:
    def repeatedNTimes(self, A):
        doubleN = len(A)
        N = doubleN / 2
        dic = {}
        for a in A:
            if a in dic.keys():
                dic[a]=dic[a]+1
            else:
                dic[a]=1
            if dic[a]==N:
                return a

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转载自www.cnblogs.com/asenyang/p/10164663.html
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