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Given an array A
of integers, a ramp is a tuple (i, j)
for which i < j
and A[i] <= A[j]
. The width of such a ramp is j - i
.
Find the maximum width of a ramp in A
. If one doesn't exist, return 0.
Example 1:
Input: [6,0,8,2,1,5] Output: 4 Explanation: The maximum width ramp is achieved at (i, j) = (1, 5): A[1] = 0 and A[5] = 5.
Example 2:
Input: [9,8,1,0,1,9,4,0,4,1] Output: 7 Explanation: The maximum width ramp is achieved at (i, j) = (2, 9): A[2] = 1 and A[9] = 1.
Note:
2 <= A.length <= 50000
0 <= A[i] <= 50000
思路:维护一个单调递减数组,然后每来一个数,二分法找比这个数小的数的位置
import bisect
class Solution(object):
def maxWidthRamp(self, A):
"""
:type A: List[int]
:rtype: int
"""
res = 0
q = [-A[0]]
q_index = [0]
for i in range(1,len(A)):
idx = bisect.bisect_left(q, -A[i])
if idx!=len(q):
res = max(res, i-q_index[idx])
else:
q.append(-A[i])
q_index.append(i)
return res