[leetcode]2sum,3sum,4sum总结

刷了50题了,本来是想50题一起总结的,发现并没有啥耐心。还是边刷边总结吧。


2sums

class Solution {
    public int[] twoSum(int[] nums, int target) {
        
        Map<Integer,Integer> map=new HashMap<>();
        for(int i=0;i<nums.length;i++){
            int remain=target-nums[i];
            if(!map.containsKey(remain)){
                map.put(nums[i],i);
            }
            else{
                int j=map.get(remain);
                return new int[]{j,i};
            }
        }
        
        return null;
       
    }
}

3sums

class Solution {
    public List<List<Integer>> threeSum(int[] nums) {
        Arrays.sort(nums);
        List<List<Integer>> res=new ArrayList<>();
        
        for(int i=0;i<nums.length;i++){
            if(i!=0 && nums[i]==nums[i-1])continue;
            
            int p=i+1;
            int q=nums.length-1;
            while(p<nums.length&&q<nums.length&&p<q){
                if(nums[p]+nums[q]<0-nums[i]){
                    p++;
                }
                else if(nums[p]+nums[q]>0-nums[i]){
                    q--;
                }
                else{
                    List<Integer> list=new ArrayList<>();
                    list.add(nums[i]);
                    list.add(nums[p]);
                    list.add(nums[q]);
                    res.add(list);
                    while(p+1<nums.length&&nums[p+1]==nums[p]){
                        p++;
                    }
                    p++;
                }
            }
            
            
        }
        return res;
    }
}

3sums closest

class Solution {
    public int threeSumClosest(int[] nums, int target) {
        Arrays.sort(nums);
        int min=Integer.MAX_VALUE;
        int res=Integer.MAX_VALUE;
        
        for(int i=0;i<nums.length;i++){
            if(i!=0 && nums[i]==nums[i-1])continue;
            
            int p=i+1;
            int q=nums.length-1;
            while(p<nums.length&&q<nums.length&&p<q){
                if(nums[p]+nums[q]<target-nums[i]){
                    if(Math.abs(target-nums[p]-nums[q]-nums[i])<min){
                        min=Math.abs(target-nums[p]-nums[q]-nums[i]);
                        res=nums[p]+nums[q]+nums[i];
                    }
                  
                    p++;
                    
                }
                else if(nums[p]+nums[q]>target-nums[i]){
                    if(Math.abs(target-nums[p]-nums[q]-nums[i])<min){
                        min=Math.abs(target-nums[p]-nums[q]-nums[i]);
                        res=nums[p]+nums[q]+nums[i];
                    }
                    q--;
                    
                }
                else{
                    return target;
                }
            }
            
            
        }
        return res;       
    }
}

4sums

class Solution {
    public int threeSumClosest(int[] nums, int target) {
        Arrays.sort(nums);
        int min=Integer.MAX_VALUE;
        int res=Integer.MAX_VALUE;
        
        for(int i=0;i<nums.length;i++){
            if(i!=0 && nums[i]==nums[i-1])continue;
            
            int p=i+1;
            int q=nums.length-1;
            while(p<nums.length&&q<nums.length&&p<q){
                if(nums[p]+nums[q]<target-nums[i]){
                    if(Math.abs(target-nums[p]-nums[q]-nums[i])<min){
                        min=Math.abs(target-nums[p]-nums[q]-nums[i]);
                        res=nums[p]+nums[q]+nums[i];
                    }
                  
                    p++;
                    
                }
                else if(nums[p]+nums[q]>target-nums[i]){
                    if(Math.abs(target-nums[p]-nums[q]-nums[i])<min){
                        min=Math.abs(target-nums[p]-nums[q]-nums[i]);
                        res=nums[p]+nums[q]+nums[i];
                    }
                    q--;
                    
                }
                else{
                    return target;
                }
            }
            
            
        }
        return res;       
    }
}

猜你喜欢

转载自blog.csdn.net/weixin_36869329/article/details/84937762
今日推荐