【CF103D】Time to Raid Cowavans(分块)

题意:

思路:院赛防AK题,然而还没来得及做就被数据出锅的题坑了……

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<string>
 4 #include<cmath>
 5 #include<iostream>
 6 #include<algorithm>
 7 #include<map>
 8 #include<set>
 9 #include<queue>
10 #include<vector>
11 #include<bitset>
12 #include<ctime>
13 using namespace std;
14 typedef long long ll;
15 typedef unsigned int uint;
16 typedef unsigned long long ull;
17 typedef pair<int,int> PII;
18 typedef vector<int> VI;
19 #define fi first
20 #define se second 
21 #define MP make_pair
22 #define N      310000
23 #define M      51
24 #define MOD 1000000007
25 #define eps 1e-8 
26 #define pi     acos(-1)
27 #define oo     1e9
28 
29 ll a[N],s[N],ans[N];
30 int n;
31 
32 struct node
33 {
34     int x,y,id;
35 }b[N];
36 
37 bool cmp(node a,node b)
38 {
39     return a.y<b.y;
40 }
41  
42 int main()
43 {
44     int n;
45     scanf("%d",&n);
46     for(int i=1;i<=n;i++) scanf("%lld",&a[i]);
47     int q;
48     scanf("%d",&q);
49     for(int i=1;i<=q;i++) 
50     {
51         scanf("%d%d",&b[i].x,&b[i].y);
52         b[i].id=i;
53     }
54      sort(b+1,b+q+1,cmp);
55     for(int i=1;i<=q;i++)
56      if(b[i].y<=(int)sqrt(n))
57      {
58           if(i>1&&b[i].y==b[i-1].y) ans[b[i].id]=s[b[i].x];
59            else
60            {
61                for(int j=1;j<=n;j++) s[j]=0;
62                for(int j=n;j>=1;j--)
63                {
64                    s[j]=a[j];
65                    if(j+b[i].y<=n) s[j]+=s[j+b[i].y];
66             }
67             ans[b[i].id]=s[b[i].x];
68            }
69      }
70       else 
71       {
72             ll t=0;
73             int j=b[i].x;
74             while(j<=n)
75             {
76                 t+=a[j];
77                 j+=b[i].y;
78             }
79             ans[b[i].id]=t;
80       }
81     for(int i=1;i<=q;i++) printf("%lld\n",ans[i]); 
82      return 0;
83 }

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转载自www.cnblogs.com/myx12345/p/10092598.html
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