python leetcode 29. Divide Two Integers

注意while循环中的加速操作

class Solution(object):
    def divide(self, dividend, divisor):
        """
        :type dividend: int
        :type divisor: int
        :rtype: int
        """
        a=abs(dividend)
        b=abs(divisor)
        if a<b:
            return 0 
        count=0 
        res=0
        while a>=b:
            d=b
            count=1
            while d+d<=a:
                d+=d
                count+=count 
            a-=d
            res+=count 
        if (dividend > 0 and divisor < 0 ) or (dividend < 0 and divisor > 0):
            res=0-res
        if res>2**31-1:
            return 2**31-1 
        elif res<-2**31:
            return -2**31 
        else:
            return res

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转载自blog.csdn.net/Neekity/article/details/84864402