一个合法的身份证号码由17位地区、日期编号和顺序编号加1位校验码组成。校验码的计算规则如下:
首先对前17位数字加权求和,权重分配为:{7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2};然后将计算的和对11取模得到值Z
;最后按照以下关系对应Z
值与校验码M
的值:
Z:0 1 2 3 4 5 6 7 8 9 10
M:1 0 X 9 8 7 6 5 4 3 2
现在给定一些身份证号码,请你验证校验码的有效性,并输出有问题的号码。
输入格式:
输入第一行给出正整数N(≤100)是输入的身份证号码的个数。随后N行,每行给出1个18位身份证号码。
输出格式:
按照输入的顺序每行输出1个有问题的身份证号码。这里并不检验前17位是否合理,只检查前17位是否全为数字且最后1位校验码计算准确。如果所有号码都正常,则输出All passed
。
输入样例1:
4
320124198808240056
12010X198901011234
110108196711301866
37070419881216001X
输出样例1:
12010X198901011234
110108196711301866
37070419881216001X
输入样例2:
2
320124198808240056
110108196711301862
输出样例2:
All passed
#include<iostream>
#include<string>
using namespace std;
int main() {
int N, m[101] = { 0 };
string num[101];
cin >> N;//身份证号的个数
int b[17] = { 7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2 };
int test=0;
for (int i = 0; i < N; i++) {
cin >> num[i];//输入一个身份证号
}
for (int i = 0; i < N; i++) {
for (int j = 0; j < 17; j++) {
if ((num[i][j] - '0') < 0 || (num[i][j] - '0') > 9) {
m[i] = -1;
break;
}
else m[i] = m[i] + b[j] * (num[i][j] - '0');
}
}
for (int i = 0; i < N; i++) {
if (m[i] != -1) m[i] = m[i] % 11;
}
for (int i = 0; i < N; i++) {
if (m[i] == 0 && (num[i][17] - '0') != 1) { cout << num[i] << endl; test++; }
else if (m[i] == 1 && (num[i][17] - '0') != 0) { cout << num[i] << endl; test++; }
else if (m[i] == 2 && num[i][17] != 'X') { cout << num[i] << endl; test++; }
else if (m[i] == 3&&(num[i][17] - '0')!=9) { cout << num[i] << endl; test++; }
else if (m[i] == 4 && (num[i][17] - '0') != 8) { cout << num[i] << endl; test++; }
else if (m[i] == 5 && (num[i][17] - '0') != 7) { cout << num[i] << endl; test++; }
else if (m[i] == 6 && (num[i][17] - '0') != 6) { cout << num[i] << endl; test++; }
else if (m[i] == 7 && (num[i][17] - '0') != 5) { cout << num[i] << endl; test++; }
else if (m[i] == 8 && (num[i][17] - '0') != 4) { cout << num[i] << endl; test++; }
else if (m[i] == 9 && (num[i][17] - '0') != 3) { cout << num[i] << endl; test++; }
else if (m[i] == 10 && (num[i][17] - '0') != 2) { cout << num[i] << endl; test++; }
else if(m[i]==-1) { cout << num[i] << endl; test++; }
}
if (test == 0) cout << "All passed";
}