[LeetCode&Python] Problem 447. Number of Boomerangs

Given n points in the plane that are all pairwise distinct, a "boomerang" is a tuple of points (i, j, k) such that the distance between i and j equals the distance between i and k (the order of the tuple matters).

Find the number of boomerangs. You may assume that n will be at most 500 and coordinates of points are all in the range [-10000, 10000] (inclusive).

Example:

Input:
[[0,0],[1,0],[2,0]]

Output:
2

Explanation:
The two boomerangs are [[1,0],[0,0],[2,0]] and [[1,0],[2,0],[0,0]]
 
class Solution(object):
    def numberOfBoomerangs(self, points):
        """
        :type points: List[List[int]]
        :rtype: int
        """
        ans=0
        for i in points:
            a={}
            for j in points:
                c=(i[0]-j[0])**2+(i[1]-j[1])**2
                if c not in a:
                    a[c]=1
                else:
                    ans+=a[c]
                    a[c]+=1
        return ans*2

  

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转载自www.cnblogs.com/chiyeung/p/10052922.html