哈夫曼编码


哈夫曼编码:

根据给定的哈夫曼树,从每个叶子节点出发回溯到树根,逆向找出最优二叉树中叶子节点的编码。

代码如下:

#define MAXLEAFNUM 50
#include<malloc.h>
#include<cstring>
typedef struct node{
	char ch;//节点表示的字符
	int weight;//权值
	int parent;//父节点下标(默认为零)
	int lchild,rchild;//左右孩子下标(默认为零)
}HuffmanTree[2*MAXLEAFNUM];

typedef char* HuffmanCode[MAXLEAFNUM+1];

/*从HT中选择parent为0且weight最小的两棵树,其序列号为s1和s2*/
void select(HuffmanTree HT,int n,int &s1,int &s2)
{
	int i,min2;
	int min1=min2=32768;
	for(i=0;i<n;i++)
	{
		if(HT[i].parent==0)
		{
			if(HT[i].weight<min1){
				min2=min1;
				min1=HT[i].weight;
				
			}else if(HT[i].weight<min2)
			{
				min2=HT[i].weight;
			}
		}
	}
	s1=min1;
	s2=min2;
}

/*构造最优二叉树*/
void createHTree(HuffmanTree HT,char *c,int *w,int n)
{
	int i,s1,s2;//
	if(n<=1)return;
	for(i=1;i<=n;i++)//初始化
	{
		HT[i].ch=c[i-1]; HT[i].weight=w[i-1];
		HT[i].parent=HT[i].lchild=HT[i].rchild=0;
	}
	for(;i<2*n;i++)//
	{
		HT[i].parent=HT[i].lchild=HT[i].rchild=0;
	}
	for(i=n+1;i<2*n;i++)
	{
		select(HT,i-1,s1,s2);
		HT[s1].parent=i; HT[s2].parent=i;
		HT[i].lchild=s1; HT[i].rchild=s2;
		HT[i].weight=HT[s1].weight+HT[s2].weight;
	}
}


/*编码*/
void HuffmanCoding(HuffmanTree HT,HuffmanCode HC,int n)
{//n个叶子结点在哈夫曼树HT中的下标为1~n,第i(1<=i<=n)个叶子的编码存放HC[i]中
	char *cd;int i,start,c,f;
	if(n<=1) return;
	cd=(char*)malloc(n*sizeof(char));  cd[n-1]='\0';
	
	for(i=1;i<=n;i++)
	{
		start=n-1;
		for(c=i,f=HT[i].parent;f!=0;c=f,f=HT[f].parent)
			if(HT[f].lchild==c) cd[--start]='0';
			else cd[--start]='1';
			
		HC[i]=(char*)malloc((n-start)*sizeof(char));
		strcpy(HC[i],&cd[start]);
	}
	free(cd);
}

/*用最优二叉树进行译码*/

void Decoding(HuffmanTree HT,int n,char *buff)
{
	int p=2*n-1;
	while(*buff)
	{
		if((*buff)=='0') p=HT[p].lchild;
		else p=HT[p].rchild;
		if(HT[p].lchild==0&&HT[p].lchild==0)
		{
			pritnf("%c",HT[p].ch);
			p=2*n-1;
		}
		buff++;
	}
}

int main()
{
	return 0;
}

猜你喜欢

转载自blog.csdn.net/wolflikeinnocence/article/details/79720210