cow routing

题目链接

双关键字最短路

#include<bits/stdc++.h>
#define inf 10000000000000000
#define maxn 1010
using namespace std;
int b[maxn][maxn],d[maxn],q[maxn],c[maxn];
long long dis[maxn],a[maxn][maxn];
bool vis[maxn];
int n,m,num,s,t,mx;

inline int read() {
	int x=0,f=1; char c=getchar();
	while(c<'0'||c>'9') {if(c=='-')f=-1; c=getchar();}
	while(c>='0'&&c<='9') x=(x<<3)+(x<<1)+c-'0',c=getchar();
	return x*f;
}
 
void spfa() {
	for(int i=1;i<=mx;i++) dis[i]=inf;
	dis[s]=0; d[s]=0;
	int l=0,r=1;
	q[1]=s; vis[s]=1;
	while(l!=r) {
		l++;
		if(l==maxn) l=0;
		int x=q[l];
		for(int i=1;i<=mx;i++)
		  if(dis[x]+a[x][i]<dis[i]||(dis[x]+a[x][i]==dis[i]&&d[x]+b[x][i]<d[i])) {
		  	dis[i]=dis[x]+a[x][i];
		  	d[i]=d[x]+b[x][i];
		  	if(!vis[i]) {
		  		r++; 
				if(r==maxn) r=0;
		  		q[r]=i; vis[i]=1;
		  	}
		  }
		vis[x]=0;
	}
}

int main() {
	freopen("cowroute.in","r",stdin);
	freopen("cowroute.out","w",stdout);
	for (int i=1;i<=1000;i++)
	 for (int j=1;j<=1000;j++) a[i][j]=inf;
	s=read(); t=read(); n=read();
	for(int i=1;i<=n;i++) {
		int len=read(),cnt=read();
		for(int j=1;j<=cnt;j++) {c[j]=read(); mx=max(mx,c[j]);}
		for(int j=1;j<cnt;j++)
		  for(int k=j+1;k<=cnt;k++)
		    if(len<a[c[j]][c[k]]||(len==a[c[j]][c[k]]&&k-j<b[c[j]][c[k]])) {
		    	a[c[j]][c[k]]=len; b[c[j]][c[k]]=k-j;
		    }
	}
	spfa();
	if(dis[t]!=inf) printf("%lld %d\n",dis[t],d[t]);
	else printf("-1 -1\n");
	return 0;
}

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转载自blog.csdn.net/MiaoZ_/article/details/83715334
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