#include<stdio.h>
#include<Windows.h>
void Mimi(int n)
{
int i = 0;
int sum = 1;
int num = 0;
if (n <= 0)
{
printf("客官用心点哦:\n");
return 0;
}
else
for (i =1;i<=n; i++)
{
sum = sum*i;
num += sum;
}
printf("%d! = %d\n", n, sum);
printf("前%d项阶乘之和为: %d\n", n, num);
}
int main()
{
int n = 0;
printf("请输入:");
scanf("%d", &n);
Mimi(n);
system("pause");
return 0;
}
n的阶乘和前n项的阶乘
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转载自blog.csdn.net/Zero_975/article/details/82827416
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