SpringSecurity(一)自定义登录界面

1. 新建一个SpringBoot工程

添加如下依赖

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-security</artifactId>
        </dependency>

        <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-thymeleaf</artifactId>
        </dependency>

2. 新建LoginController,设置登录页面的路由。

@Controller
public class LoginController {

    @GetMapping("/authentication/login")
    public String authenticationLogin() throws IOException {
        return "login";
    }
}

login页面的html代码如下

<!DOCTYPE html>
<html lang="en" xmlns:th="http://www.w3.org/1999/xhtml">
<head>
    <title>登录</title>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1">
    <link rel="stylesheet" href="https://cdn.staticfile.org/twitter-bootstrap/4.1.0/css/bootstrap.min.css">
    <script src="https://cdn.staticfile.org/jquery/3.2.1/jquery.min.js"></script>
    <script src="https://cdn.staticfile.org/popper.js/1.12.5/umd/popper.min.js"></script>
    <script src="https://cdn.staticfile.org/twitter-bootstrap/4.1.0/js/bootstrap.min.js"></script>
</head>
<body>
<div class="container">
    <div class="row" style="margin-top: 20px;">
        <div class="col-md-3">
            <h2>登陆</h2>
            <form th:action="@{/authentication/form}" method="post">
                <div class="form-group">
                    <label for="username">Username</label>
                    <input type="text" class="form-control" id="username" name="username" placeholder="Enter username">
                </div>
                <div class="form-group">
                    <label for="Password">Password:</label>
                    <input type="password" class="form-control" id="Password" name="password" placeholder="Enter password">
                </div>

                <div class="form-group" th:if="${param.error}">
                    <p th:if="${session.SPRING_SECURITY_LAST_EXCEPTION}">
                    <p th:text="${session.SPRING_SECURITY_LAST_EXCEPTION.message}"></p>
                    </p>
                </div>

                <button type="submit" class="btn btn-primary">Submit</button>
            </form>
        </div>
    </div>
</div>

</body>
</html>

3.  新建SpringSecurityConfig

@Configuration
@EnableWebSecurity
public class SpringSecurityConfig extends WebSecurityConfigurerAdapter {

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.authorizeRequests()
                .antMatchers("/authentication/*","/login") // 不需要登录就可以访问
                .permitAll()
                .antMatchers("/user/**").hasAnyRole("USER") // 需要具有ROLE_USER角色才能访问
                .antMatchers("/admin/**").hasAnyRole("ADMIN") // 需要具有ROLE_ADMIN角色才能访问
                .anyRequest().authenticated()
                .and()
                    .formLogin()
                    .loginPage("/authentication/login") // 设置登录页面
                    .loginProcessingUrl("/authentication/form")
                    .defaultSuccessUrl("/user/index") // 设置默认登录成功后跳转的页面
                ;
    }

    // 密码加密方式
    @Bean
    public PasswordEncoder passwordEncoder(){
        return new BCryptPasswordEncoder();
    }
    // 重写方法,自定义用户
    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.inMemoryAuthentication().withUser("lzc").password(new BCryptPasswordEncoder().encode("123456")).roles("ADMIN","USER");
        auth.inMemoryAuthentication().withUser("zhangsan").password(new BCryptPasswordEncoder().encode("123456")).roles("USER");
    }
}

4. 测试。

访问/user/index,将会跳转到如下页面

输入正确的账号和密码

而实际应用中,用户的账号和密码肯定不是写死在程序中的,下一篇将会介绍如何从数据库中获取用户进行登录。

代码地址  : https://github.com/923226145/SpringSecurity/tree/master/chapter1

猜你喜欢

转载自blog.csdn.net/lizc_lizc/article/details/83998582