[递归] 八皇后问题 - C语言

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#include<stdio.h>

int count=0;//统计一共有几种

int notDanger(int row,int j,int (*chess)[8]) {
	int i,k,flag1=0,flag2=0,flag3=0,flag4=0,flag5=0;
	//判断竖方向
	for (i=0; i<8; i++) {
		if ( chess[i][j] !=0 ) {
			flag1 = 1;
			break;
		}
	}
	//判断左上方
	for (i=row,k=j; i>=0&&k>=0; i--,k--) {
		if (chess[i][k]!=0) {
			flag2 = 1;
			break;
		}
	}
	//判断右下方
	for (i=row,k=j; i<8&&k<8; i++,k++) {
		if (chess[i][k]!=0) {
			flag3 = 1;
			break;
		}
	}
	//判断右上方
	for (i=row,k=j; i>=0&&k<8; i--,k++) {
		if (chess[i][k]!=0) {
			flag4 = 1;
			break;
		}
	}
	//左下方
	for (i=row,k=j; i<8&&k>0; i++,k--) {
		if (chess[i][k]!=0) {
			flag5 = 1;
			break;
		}
	}
	if (flag1 || flag2 || flag3 ||flag4 ||flag5) 
		return 0;
	else 
		return 1;
}

//row起始行 n列数 (*chess)[8]指向棋盘每一行的指针
void eightQueen(int row,int n,int (*chess)[8] ) {
	int chess2[8][8],i,j;
	for (i=0; i<8; i++) {
		for (j=0; j<8; j++) {
			chess2[i][j]=chess[i][j];
		}
	}
	if (8 == row) {
		printf("第%d种\n",++count);
		for (i=0; i<8; i++) {
			for (j=0; j<8; j++) {
				printf("%d",chess2[i][j]);
			}
			printf("\n");
		}
		printf("\n");
	}
	else {
		//判断这个位置是否有危险
		//如果没有危险,继续往下
		for (j=0; j<n; j++) {
			if (notDanger(row,j,chess)) {//判断是否危险
				for(i=0; i<8; i++) {
					*(*(chess2+row)+i)=0;
				}
				*(*(chess2+row)+j)=1;
				eightQueen(row+1,n,chess2);
			}
			
		}
	}
}

int main() {
	int chess[8][8],i,j;
	for (i=0; i<8; i++) {
		for (j=0; j<8; j++) {
			chess[i][j]=0;
		}
	}
	eightQueen(0,8,chess);
	printf("总共有解决方法%d",count);
	return 0;
}

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转载自blog.csdn.net/summer_dew/article/details/83922473
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