LeetCode 1:两数之和

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题目
给定一个整数数组和一个目标值,找出数组中和为目标值的两个数。你可以假设每个输入只对应一种答案,且同样的元素不能被重复利用。
示例
给定 nums = [2, 7, 11, 15], target = 9
因为 nums[0] + nums[1] = 2 + 7 = 9
所以返回 [0, 1]

C++版本解答:

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        vector<int> result;
        int n=nums.size();
        for(int i=0;i<n;i++){
            for(int j=i+1;j<n;j++){
                if(nums[i]+nums[j]==target){
                    result.push_back(i);
                    result.push_back(j);
                    break;
                }
            }
            if(!result.empty()){
                break;
            }
        }
        return result;
    }
};

Python版本解答:

class Solution:
    def twoSum(self, nums, target):
        """
        :type nums: List[int]
        :type target: int
        :rtype: List[int]
        """
        for i in range(len(nums)):
            for j in range(i+1, len(nums)):
                if nums[i]+nums[j] == target:
                    return '[%s,%s]'%(i,j)
        return None

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转载自blog.csdn.net/Stripeybaby/article/details/80153384