给定一个链表,判断链表中是否有环。
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if (head == null || head.next == null) {
return false;
}
ListNode slow = head;
ListNode fast = head.next;
while (slow != fast) {
//只要有一个为空,则无环
if (fast == null || fast.next == null) {
return false;
}
//移动快慢指针
slow = slow.next;
fast = fast.next.next;
}
return true;
}
}