js如何获取前后连续n天的时间

 1 function GetDateStr(AddDayCount) { 
 2    var dd = new Date();
 3    dd.setDate(dd.getDate()+AddDayCount);//获取AddDayCount天后的日期
 4    var y = dd.getFullYear(); 
 5    var m = (dd.getMonth()+1)<10?"0"+(dd.getMonth()+1):(dd.getMonth()+1);//获取当前月份的日期,不足10补0
 6    var d = dd.getDate()<10?"0"+dd.getDate():dd.getDate();//获取当前几号,不足10补0
 7    return y+"-"+m+"-"+d; 
 8 }
 9  
10  
11 console.log("半年前:"+GetDateStr(-180));
12 console.log("三月前:"+GetDateStr(-90));
13 console.log("一月前:"+GetDateStr(-30));
14 console.log("昨天:"+GetDateStr(-1));
15 console.log("今天:"+GetDateStr(0));
16 console.log("明天:"+GetDateStr(1));
17 console.log("后天:"+GetDateStr(2));
18 console.log("一月后:"+GetDateStr(30));
19 console.log("三月后:"+GetDateStr(90));
20 console.log("半年后:"+GetDateStr(180)); 

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转载自www.cnblogs.com/yangguoe/p/9930005.html
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