c语言判断一个年份是否是闰年

思路是将年份分别除以4,100,400的余数分别存在four,hundred,fourhundred变量中然后只有两种情况是闰年其他不是

#include <stdio.h>
void main()
{
int four , hundred , fourhundred , year;
scanf("%d",&year);
four = year % 4;
hundred = year % 100;
fourhundred = year % 400;
if (four == 0 && hundred == 0 && fourhundred == 0)
 printf("this %d is a leap year.", year);
else if (four == 0 && hundred != 0 && fourhundred != 0)
 printf("this %d is a leap year.", year);
else printf("this %d is not a leap %d.",year);
}

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转载自blog.csdn.net/viafcccy/article/details/83628920
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