通过MapReduce寻找好友列表数据中的共同好友

以下是qq的好友列表数据,冒号前是一个用户,冒号后是该用户的所有好友(数据中的好友关系是单向的)

A:B,C,D,F,E,O

B:A,C,E,K

C:F,A,D,I

D:A,E,F,L

E:B,C,D,M,L

F:A,B,C,D,E,O,M

求出哪些人两两之间有共同好友,及他俩的共同好友都有谁?

解题思路:

用两个步骤解决

第一步:找出每一个人,是哪些人的共同好友

map

读一行   A:B,C,D,F,E,O

输出    <B,A><C,A><D,A><F,A><E,A><O,A>

在读一行   B:A,C,E,K

输出   <A,B><C,B><E,B><K,B>

reduce

拿到的数据比如<C,A><C,B><C,E><C,F><C,G>......

输出: 

<A-B,C>

<A-E,C>

<A-F,C>

<A-G,C>

<B-E,C>

<B-F,C>.....

第二步:将共同好友两两配对,作为key,发出去

map

读入一行<A-B,C>

直接输出<A-B,C>

reduce

读入数据  <A-B,C><A-B,F><A-B,G>.......

输出: A-B  C,F,G,.....

以下是代码实现:

public class SharedFriendsStepOne {

	static class SharedFriendsStepOneMapper extends Mapper<LongWritable, Text, Text, Text> {
		@Override
		protected void map(LongWritable key, Text value, Context context) throws IOException, InterruptedException {
			// A:B,C,D,F,E,O
			String line = value.toString();
			String[] person_friends = line.split(":");
			String person = person_friends[0];
			String friends = person_friends[1];
			for (String friend : friends.split(",")) {
				// 输出<好友,人>
				context.write(new Text(friend), new Text(person));
			}
		}
	}

	static class SharedFriendsStepOneReducer extends Reducer<Text, Text, Text, Text> {
		@Override
		protected void reduce(Text friend, Iterable<Text> persons, Context context) throws IOException, InterruptedException {
			StringBuffer sb = new StringBuffer();
			for (Text person : persons) {
				sb.append(person).append(",");
			}
			context.write(friend, new Text(sb.toString()));
		}
	}

	public static void main(String[] args) throws Exception {
		Configuration conf = new Configuration();

		Job job = Job.getInstance(conf);
		job.setJarByClass(SharedFriendsStepOne.class);

		job.setOutputKeyClass(Text.class);
		job.setOutputValueClass(Text.class);
		
		job.setMapperClass(SharedFriendsStepOneMapper.class);
		job.setReducerClass(SharedFriendsStepOneReducer.class);

		FileInputFormat.setInputPaths(job, new Path("D:/srcdata/friends"));
		FileOutputFormat.setOutputPath(job, new Path("D:/temp/out"));

		job.waitForCompletion(true);
	}
}
public class SharedFriendsStepTwo {

	static class SharedFriendsStepTwoMapper extends Mapper<LongWritable, Text, Text, Text> {
		// 拿到的数据是上一个步骤的输出结果
		// A I,K,C,B,G,F,H,O,D,
		// 友 人,人,人
		@Override
		protected void map(LongWritable key, Text value, Context context) throws IOException, InterruptedException {
			String line = value.toString();
			String[] friend_persons = line.split("\t");
			String friend = friend_persons[0];
			String[] persons = friend_persons[1].split(",");
			//排序,防止C-B和B-C被当成两种情况发往reduce
			Arrays.sort(persons);
			for (int i = 0; i < persons.length - 1; i++) {
				for (int j = i + 1; j < persons.length; j++) {
					// 发出 <人-人,好友> ,这样,相同的“人-人”对的所有好友就会到同1个reduce中去
					context.write(new Text(persons[i] + "-" + persons[j]), new Text(friend));
				}
			}
		}
	}

	static class SharedFriendsStepTwoReducer extends Reducer<Text, Text, Text, Text> {
		@Override
		protected void reduce(Text person_person, Iterable<Text> friends, Context context) throws IOException, InterruptedException {
			StringBuffer sb = new StringBuffer();
			for (Text friend : friends) {
				sb.append(friend).append(" ");
			}
			context.write(person_person, new Text(sb.toString()));
		}
	}

	public static void main(String[] args) throws Exception {
		Configuration conf = new Configuration();

		Job job = Job.getInstance(conf);
		job.setJarByClass(SharedFriendsStepTwo.class);

		job.setOutputKeyClass(Text.class);
		job.setOutputValueClass(Text.class);

		job.setMapperClass(SharedFriendsStepTwoMapper.class);
		job.setReducerClass(SharedFriendsStepTwoReducer.class);

		FileInputFormat.setInputPaths(job, new Path("D:/temp/out/part-r-00000"));
		FileOutputFormat.setOutputPath(job, new Path("D:/temp/out2"));

		job.waitForCompletion(true);
	}
}

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转载自blog.csdn.net/weixin_36490014/article/details/82015634
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