js去除url中指定参数

在项目中,遇到有参数只需要弹出一次,弹出后返回时就会再次弹出,所以需要将弹出参数取消:
代码如下:

function delParam(paramKey) {
        var url = window.location.href;    //页面url
        var urlParam = window.location.search.substr(1);   //页面参数
        var beforeUrl = url.substr(0, url.indexOf("?"));   //页面主地址(参数之前地址)
        var nextUrl = "";

        var arr = new Array();
        if (urlParam != "") {
            var urlParamArr = urlParam.split("&"); //将参数按照&符分成数组
            for (var i = 0; i < urlParamArr.length; i++) {
                var paramArr = urlParamArr[i].split("="); //将参数键,值拆开
                //如果键雨要删除的不一致,则加入到参数中
                if (paramArr[0] != paramKey) {
                    arr.push(urlParamArr[i]);
                }
            }
        }
        if (arr.length > 0) {
            nextUrl = "?" + arr.join("&");
        }
        url = beforeUrl + nextUrl;
        return url;
    }

猜你喜欢

转载自blog.csdn.net/qq_38906555/article/details/82688586