获取url中指定参数

1.方法一:

function getQueryString(name) {
    var reg = new RegExp('(^|&)' + name + '=([^&]*)(&|$)', 'i');
    var r = window.location.search.substr(1).match(reg);
    if (r != null) {
        return unescape(r[2]);
    }
    return null;
}
// 这样调用:
alert(GetQueryString("参数名1"));
alert(GetQueryString("参数名2"));
alert(GetQueryString("参数名3"));

2.方法二:

function GetRequest() {
    var url = location.search; //获取url中"?"符后的字串
    var theRequest = new Object();
    if (url.indexOf("?") != -1) {
        var str = url.substr(1);
        strs = str.split("&");
        for(var i = 0; i < strs.length; i ++) {
            theRequest[strs[i].split("=")[0]] = unescape(strs[i].split("=")[1]);
        }
    }
    return theRequest;
}
var Request = new Object();
Request = GetRequest();
// var 参数1,参数2,参数3,参数N;
// 参数1 = Request['参数1'];
// 参数2 = Request['参数2'];
// 参数3 = Request['参数3'];
// 参数N = Request['参数N'];

3.方法三:

function GetQueryString(name) {  
    var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");  
    var r = window.location.search.substr(1).match(reg);  //获取url中"?"符后的字符串并正则匹配
    var context = "";  
    if (r != null)  
         context = r[2];  
    reg = null;  
    r = null;  
    return context == null || context == "" || context == "undefined" ? "" : context;  
}
alert(GetQueryString("q")); 

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转载自blog.csdn.net/tt18473481961/article/details/81011079
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