题目:
Implement the following operations of a stack using queues.
push(x) --Push element x onto stack.
pop() – Removes the element on top of the
stack. top() – Get the top element.
empty() – Return whether the stack is empty.
Example:MyStack stack = new MyStack(); stack.push(1); stack.push(2); stack.top(); // returns 2 stack.pop(); // returns 2 stack.empty(); // returns false
Notes:
1.You must use only standard operations of a queue – which means onlypush to back
,peek/pop from front
,size
, andis empty
operations are valid.
2.Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
3.You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
解释:
用队列来实现栈。核心思想就是不断地pop()
,然后不断地append()
。
python代码:
class MyStack(object):
def __init__(self):
"""
Initialize your data structure here.
"""
self._queue=[]
def push(self, x):
"""
Push element x onto stack.
:type x: int
:rtype: void
"""
self._queue.append(x)
def pop(self):
"""
Removes the element on top of the stack and returns that element.
:rtype: int
"""
#直接把最后一个元素弹出即可,不需要再append了,所以是len()-1
for i in xrange(len(self._queue)-1):
self._queue.append(self._queue.pop(0))
return self._queue.pop(0)
def top(self):
"""
Get the top element.
:rtype: int
"""
#这样做是为了不改变queue本身的结构
top=None
for i in xrange(len(self._queue)):
top=self._queue.pop(0)
self._queue.append(top)
return top
def empty(self):
"""
Returns whether the stack is empty.
:rtype: bool
"""
return self._queue==[]
# Your MyStack object will be instantiated and called as such:
# obj = MyStack()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.top()
# param_4 = obj.empty()
c++代码:
#include<queue>
using namespace std;
class MyStack {
public:
/** Initialize your data structure here. */
queue<int>_queue;
MyStack() {
}
/** Push element x onto stack. */
void push(int x) {
_queue.push(x);
}
/** Removes the element on top of the stack and returns that element. */
int pop() {
for (int i=0;i<_queue.size()-1;i++)
{
int tmp=_queue.front();
_queue.pop();
_queue.push(tmp);
}
int tmp=_queue.front();
_queue.pop();
return tmp;
}
/** Get the top element. */
int top() {
int tmp=0;
for (int i=0;i<_queue.size();i++)
{
tmp=_queue.front();
_queue.pop();
_queue.push(tmp);
}
return tmp;
}
/** Returns whether the stack is empty. */
bool empty() {
return _queue.empty();
}
};
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* bool param_4 = obj.empty();
*/
总结:
这种设计题还是要好好学一下的。