【leetcode】【套路题】476. Number Complement

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一、题目描述

Given a positive integer, output its complement number. The complement strategy is to flip the bits of its binary representation.

Note:

  1. The given integer is guaranteed to fit within the range of a 32-bit signed integer.
  2. You could assume no leading zero bit in the integer’s binary representation.

Example 1:

Input: 5
Output: 2
Explanation: The binary representation of 5 is 101 (no leading zero bits), and its complement is 010. So you need to output 2.

Example 2:

Input: 1
Output: 0
Explanation: The binary representation of 1 is 1 (no leading zero bits), and its complement is 0.

思路:这种题没什么办法,记住这个套路吧。举个例子,num = 00000101时,另mask = ~0 = 11111111,让mask变为 11111000,然后计算~mask & ~num即可得到结果


代码:

class Solution {
public:
    int findComplement(int num) {
        unsigned mask = ~0;
        while(mask & num){
            mask = mask << 1;
        }
        return ~mask & ~num;
        
    }
};






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转载自blog.csdn.net/xiaoquantouer/article/details/77188423